Just peanuts

Three kids share 770 peanuts. Every time Alan gets 4 peanuts, Boris gets 3 peanuts, and every time Alan gets 6 peanuts, Carla gets 7 peanuts.

How many peanuts does Alan get?

Problem source: Mattenøtter, Teknisk Ukeblad.

4 Responses to “Just peanuts”

  1. Michael Maguire Says:

    A+(3/4•A)+(7/6•A)=770
    A•(1+9/12+14/12)=770
    A•(35/12)=770
    A=770•12/35=264

    Alan gets 264.
    Boris gets 198.
    Carla gets 308.

    I’m going to share this with my son. Thanks for the problem!

  2. Mike Anderson Says:

    MM:

    Many of my students are afraid of fractions, so I rephrased the conditions as “peanut odds” for Alan:Boris:Carla. The odds are 12:9:14, comprising 35 parts in all. Then 770/35 = 22 peanuts per part, and multiplication gives the (same) answer.

    Nice problem!

  3. Michael Maguire Says:

    MA:

    One of the things I love most about math beyond simple arithmetic is that there are often multiple equally correct approaches. Maybe it’s because statistics has never been a strength of mine but that approach leaves me scratching my head. Out of curiosity, with your eye for statistics, do the odds of 12:9:14 just leap out at you without much effort? Maybe it’s time for me to find a statistics course at the local community college.

    To whoever it may concern:

    Mattenøtter apparently has some gems in it but unfortunately I need a translator. Please feel free to post more of them!

  4. Jan Nordgreen Says:

    In my class room I have seen that even simple arithmetic can give multiple equally correct approaches. :)

    More problems will come from this Norwegian source (Norwegian is my mother tongue).

    Google translated it like this to English:

    This task is about three children – John, Peter and Kari – who share a bag of 770 peanuts.

    Every time John gets 4 peanuts, get Per 3 peanuts, and every time John gets 6 peanuts, get Kari 7 peanuts.

    How many peanuts are Ola?

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