Comments for thnik again!

Comment on Think outside the box by John Smith

John Smith — Mon, 21 May 2012 01:00:08 +0000

Really guys?…the horizantal force is gravity. Gravity is always constant…as far as we know lol. If there were no firction between the two the box would still be pulled towards the floor of the train. If the train were moving the box would still be on the floor, but at the back of the train do to a pocket of air between the two (Casimir effect) and even if not that then the fact that with no friction that would imply that all the molecules in both the floor and the box were aligned perfect enough to repell each other to keep each other apart. None the less the box would still be on the floor due to gravity…otheriwse, if not, the box would be floating in the air and in some strange way youd have antigravity lol. Inertia is the result of a force apllied to an object. If friction were still in play then the only thing that would send the box to the back of the train, like Robert said, would be the force of the train over coming the friction between the floor and the box. Same result if the train stopped. If it stopped slow enough the box wouldnt move. If it stopped faster the the inertia gained from the train moving then the box would fly forward at the speed of its inertia minus the friction that was tryin to keep it on the floor….jus me but i wouldnt wana stand in its way if it does lol.

Comment on Quote by Jude

Jude — Sat, 05 May 2012 01:12:38 +0000

Wow…you sound like a lot of fun, Richard. Pretty subjective comment too. Do you even understand the quote?

Comment on High five by RJB

RJB — Thu, 03 May 2012 12:46:21 +0000

I think you mean 5/5 in the first brackets

Comment on This is the solution, what is the puzzle? by Kenosis23

Kenosis23 — Wed, 25 Apr 2012 22:48:01 +0000

Mike, I suspect that there is a potentially infinite problems to this solution — in fact that was my hidden point. Yours is good but maybe needlessly complicated. One solution: “Arrange six colored spheres in a a triangle so that no two touching spheres are colored the same.” There are many more “problems” and some more interesting.

Comment on Happy New Year! by Jan Nordgreen

Jan Nordgreen — Wed, 07 Mar 2012 22:43:23 +0000

And one may use Mathematika:
http://blog.wolfram.com/2012/02/02/happy-109876-54321/

Comment on Happy New Year! by Richard Sabey

Richard Sabey — Wed, 07 Mar 2012 10:04:10 +0000

Using just 987654321:
2012 = 9*8*7*(6-5)*4 -3-2+1

Some delights for future years:
2013 = (65-4)*(32+1)
2015 = 8*(7+6+5)*(4+3)*2 – 1
2016 = (7+6-5)*4*3*21
2017 = 8*(7+6+5)*(4+3)*2 + 1

Comment on Happy New Year! by Richard Sabey

Richard Sabey — Wed, 07 Mar 2012 09:37:44 +0000

2012 = [ (1+0+9)+(8+7)*(6+5)*4 ] * 3 + 2*1
2013 = [ (1+0+9)+(8+7)*(6+5)*4 ] * 3 + 2 + 1
2014 = {(1+0+9)*[(8+7+6)*5-4] – 3} *2*1
2015 = (1+0+9+8)*7*(6+5+4+3-2) – 1
2016 = (1+0+9+8)*7*(6+5+4+3-2)*1
2017 = (1+0+9+8)*7*(6+5+4+3-2) + 1

Found using a program I’d already written, to solve problems just like this one. The first operation it tries is addition, hence the preference for expressions that start with a chain of additions of single-digit numbers.

Comment on Quote by Larry Seger

Larry Seger — Mon, 05 Mar 2012 14:51:43 +0000

Lets put the 10 commandments and Calvin and Hobbes together and see what we get
http://www.grymonpre.com/math/chmath.htm

Comment on Is 1 a prime number? by Richard Sabey

Richard Sabey — Sat, 03 Mar 2012 16:29:47 +0000

1 is not a prime. Why? Because this follows from the definition of “prime”. Why not define “prime” in a way that makes 1 a prime? Because then you lose the fundamental theorem of arithmetic.

Comment on Is 1 a prime number? by Jan Nordgreen

Jan Nordgreen — Sat, 03 Mar 2012 08:38:19 +0000

Why do you ask?